Gaseous hydrogen, which is under normal conditions in a closed vessel with a volume of v = 5 liters, was cooled to delta T = 55 K.

Gaseous hydrogen, which is under normal conditions in a closed vessel with a volume of v = 5 liters, was cooled to delta T = 55 K. Find the increment in the internal energy of the gas and the amount of heat released.

Given:
P1 = 101325
T1 = 273
V = 5
R = 8.3144
deltaT = -55
To find:
deltaU;
Qotd
Decision:
Let us find the number of moles of gaseous hydrogen n in the vessel from the Cliperon equation:
n = P1 * V / R * T1
Change in the internal energy of the gas:
deltaU = 5/2 * n * R * deltaT
deltaU = -255.168 J
from the first hackon of thermodynamics:
Qotd = -delta U
Qotd = 255.168 J