Get the following alcohol in any way, then write the equation for its reaction with propionic acid: butanol-2

1. Getting butanol – 2.

CH3 – CHCL – CH2 – CH3 + NaOH = CH3 – CHOH – CH2 – CH3 + NaCL.

The interaction of 2 – butane chlorine with sodium hydroxide results in the formation of a butanol – 2 compound and sodium chloride.

2. The interaction of butanol – 2 with propionic acid. Esterification reaction.

CH3 – CHOH – CH2 – CH3 + H3C – CH2 – COOH = H3C – CH2 – COOCH – CH2 – CH3

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CH3

When butanol-2 interacts with propionic acid, water and ether are formed as a result.



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