Give the formula for a simple gaseous substance that is lighter than the fourth member

Give the formula for a simple gaseous substance that is lighter than the fourth member of the homologous series of alkanes, but heavier than the third member of the same series. Write one equation for the reaction that this substance enters into.

The third member of the homologous series is propane C₃H₈. Its molar mass is 44 grams per mole. The fourth member of the homologous series is butane C4H10. Its molar mass is 58.12 grams per mole. A simple gaseous substance that is lighter than butane and heavier than propane can be ozone (O3). Its molar mass is 48 grams per mole.



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