Given 20 liters of acetylene. How much oxygen will it take to burn all the acetylene?

The oxidation reaction of acetylene with oxygen is described by the following chemical reaction equation:

2C2H2 + 5O2 = 4CO2 + 2H2O;

2 moles of acetylene are reacted with 5 moles of oxygen.

Let’s calculate the available chemical amount of the acetylene substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N C2H2 = 20 / 22.4 = 0.893 mol;

To burn such an amount of matter, you need to take 0.893 x 5/2 = 2.233 mol of oxygen.

Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V O2 = 2.233 x 22.4 = 50 liters;