Given a circle with center O. AC and BC – diameters. The central angle AOD is 144 degrees. Find the inscribed corner.

The central angle of the AOD is adjacent to the central angle of the AOB, the sum of which is 180, then the angle AOB = (180 – AOD) = (180 – 144) = 36.

The central angle AOB rests on the arc AB, then the degree measure of the arc AB is 36.

The inscribed angle ACB also rests on the arc AB, then the degree measure of the angle ACB is equal to half the degree measure of the arc. Angle ACB = 36/2 = 180.

Answer: The inscribed angle ACB is 180.



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