Given a circle (x + 5) ^ 2 + (y-3) ^ 2 = 49 find the diameter and in which quarter is the center of this circle.

The equation of the circle in the Cartesian coordinate system has the form: (x-a) ^ 2 + (y-b) ^ 2 = R ^ 2, where R is the radius of the circle, (a; b) are the coordinates of the center.
We have the equation of the circle: (x + 5) ^ 2 + (y-3) ^ 2 = 49;
(x – (- 5)) ^ 2+ (y-3) ^ 2 = 49.
Taking the square root of 49, we find the radius. It is 7, therefore, the diameter is 7 * 2 = 14.
The coordinates of the center of this circle (-5; 3), which means its center is located in the second coordinate quarter.