Given a function y = f (x), where f (x) = – 3x + 2. Find: a) f (0), f (2/3), f (-3), f (-1/2)

A function is given y = f (x), where f (x) = -3 * x + 2.

Let’s find the values of the functions in points.

To do this, we substitute the known points into the function itself and calculate its value. That is, we get:

1) f (0) = -3 * 0 + 2 = 0 + 2 = 2;

2) f (2/3) = -3 * 2/3 + 2 = -3/3 * 2 + 2 = -1/1 * 2 + 2 = -1 * 2 + 2 = -2 + 2 = 2 – 2 = 0;

3) f (-3) = -3 * (-3) + 2 = 3 * 3 + 2 = 9 + 2 = 11;

4) f (-1/2) = -3 * (-1/2) + 2 = 3 * 1/2 + 2 = 3/2 + 2 = 1.5 + 2 = 3.5.