Given a function y = -x ^ 2-4x + 5, calculate the values of this function at x = -2 and x = -6.

Given a function y = -x ^ 2-4x + 5, calculate the values of this function at x = -2 and x = -6. Write down the sum of the resulting values.

1. Find the values of the quadratic function at the given points:

y = -x ^ 2 – 4x + 5;

1) x = -2;

y (-2) = – (- 2) ^ 2 – 4 * (-2) + 5 = -4 + 8 + 5 = 9;

2) x = -6;

y (-6) = – (- 6) ^ 2 – 4 * (-6) + 5 = -36 + 24 + 5 = -7.

2. The sum of the values of the function at these points:

s = y (-2) + y (-6);
s = 9 – 7 = 2.
Answer:

1.y (-2) = 9; y (-6) = -7;
2.s = 2.