Given a parallelogram ABCD, angle A = 90, CD = 7, angle ABD is equal to the angle DBC. Find the perimeter and area ABCD

angle A is 90 degrees, then all other angles are also equal to 90 degrees, therefore ABCD is a rectangle. Since the angle ABD is equal to the angle DBC, and the whole angle B is equal to 90 degrees, then triangles ABD and CBD are equal in two angles and a side, therefore ABCD is a square. Its perimeter is 8 * 4 = 32. Its area is 8 * 8 = 64.