Given a parallelogram ABCD, its diagonals meet at point O. prove that triangle AOD = triangle COB.
| September 15, 2021 | education
In a parallelogram, opposite sides are equal and parallel, then BC = AD.
Angle CAD = ACB as criss-crossing angles at the intersection of parallel straight lines BC and AD secant AC.
Angle CBD = ADB as cross-lying angles at the intersection of parallel straight lines ВС and АD of secant ВD.
Then the triangles AOD and BOС are equal in side and two adjacent angles, as required.
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