# Given a parallelogram, the acute angle of which is 60 degrees and the small side is 10 cm

Given a parallelogram, the acute angle of which is 60 degrees and the small side is 10 cm a) find the height of the parallelepiped, b) find the length of the larger side of the parallelepiped, if it is known that the area of the parallelogram is 127 cm2

Through the given area, angle and smaller side, we determine the length of the larger side.

Savsd = AB * AD * SinA.

AD = Savsd * SinA / AB = 127 * Sin60 / 10 = 127 * √3 / 20 = 6.35 * √2 cm.

Also Savsd = AD * BH.

BН = Savsd / АD = 127 / 6.35 * √2 = 20 / √2 = 10 * √2 cm.

Answer: The height of the parallelogram is 10 * √2 cm, the length of the longer side is 6.35 * √2 cm.

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