Given a rectangle ABCD, where AB = 3 cm, and the diagonal BD = 10 cm.

univerkov | April 18, 2021 | education

Given a rectangle ABCD, where AB = 3 cm, and the diagonal BD = 10 cm. Find the perimeter of the corner DOC, where O is the intersection point of the diagonals.

In a rectangle, the opposite sides are equal, and the diagonals, at the point of their intersection, are halved.

Then AB = BC = 3 cm, BO = DO = 10/2 = 5 cm.

Pdos = 3 + 5 + 5 = 13 cm.

Answer: P = 13 cm.

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