Given a rectangle. Its width is 6 dm, and its length is 2 times greater. Find out the area and perimeter of the rectangle.

In order to find the area and perimeter of a rectangle, you need to know the value of its length.

Since it is 2 times larger than the width, it will be:

6 * 2 = 12 dm.

The perimeter of a rectangle is the sum of its sides and will be equal to:

6 + 12 + 6 + 12 = 12 + 24 = 36 dm.

The area of a rectangle is expressed as the product of width and length.

Therefore, we get:

12 * 6 = 72 dm2

Answer: The perimeter is 36 dm2, the area of the rectangle is 72 dm2.