Given a rectangle parallelepiped Its length is 9 cm, width is 3 cm, height is 7 cm. Find: a) the surface area of the parallelepiped
Given a rectangle parallelepiped Its length is 9 cm, width is 3 cm, height is 7 cm. Find: a) the surface area of the parallelepiped b) the sum of the lengths of all the edges of the parallelepiped c) the volume of the parallelepiped
1. By the statement of the problem, all three dimensions of the parallelepiped are known.
2. The area of the entire surface is equal to the sum of the areas of the two bases and side faces.
s base = width * length = 9 cm * 3 cm = 27 cm².
s side = perimeter * height = 2 * (width + length) * 7 cm = 2 * (9 cm + 3 cm) * 7 cm = 84 cm².
S = 2 * s main + s side = 2 * 27 cm² + 84 cm² = 138 cm².
3. The sum of all edges is equal to two perimeters of the bases plus 4 heights.
2 * 2 * (9 cm + 3 cm) + 4 * 7 cm = 48 cm + 28 cm = 76 cm.
4. Let’s calculate the volume by the formula
V = S main * height = 27 cm² * 7 cm = 189 cm³.