Given a rectangular area of 42 cm², one of its sides is 7 cm. Find the perimeter of the rectangle.

Given: ABCD – rectangle, Sabcd = 42cm ^ 2, BC = 7cm
Search: Pabcd
Decision:
1.S = ab
Sabcd = BC * AB
AB = Sabcd / BC
AB = 6cm
2. AB = CD = 6cm by the property of a rectangle
BC = AD = 7cm by rectangle property
3.P = a + a + b + b
Pabcd = AB + CD + BC + AD
Pabcd = 6 + 6 + 7 + 7
Pabcd = 26cm
Answer: Pabcd = 26cm