Given a rectangular trapezoid ABCD where angle A is a straight line from the vertex of angle A

Given a rectangular trapezoid ABCD where angle A is a straight line from the vertex of angle A, the bisector passing through point C of angle D is equal to 27 degrees find angles ACD

Since, by condition, AC is the bisector of the right angle, then the angle BAC = CAD = 90/2 = 45.

Determine the value of the angle ACD of the triangle ACD.

The sum of the inner angles of the triangle is 180, then the angle ACD = 180 – CAD – ADC = 180 – 45 – 27 = 108.

Answer: Angle ACD is 108.