Given a rhombus ABCD. The CAD angle is 40 degrees. Find the corners of the diamond.

Since ABCD is a rhombus, the lengths of all its sides are equal. AB = BC = CD = AD.

Then the triangles ABC and ACD are equal on three sides, which means that the angle BAC = CAD = 40.

Angle BAD = BAC + CAD = 40 + 40 = 80.

In a rhombus, the sum of adjacent angles is 1800, then the angle ABC = 180 – BAC = 180 – 80 = 100.

The opposite angles of the rhombus are equal, then the head BCA = BAC = 80, the angle ADC = ABC = 100.

Answer: The angles of the rhombus are 80, 100, 80, 100.