Given a trapezoid ABCD. A 6 cm long segment MN is drawn from the BA side to the CD side and divides

Given a trapezoid ABCD. A 6 cm long segment MN is drawn from the BA side to the CD side and divides the sides BA and CD in half. The height BE is 5 cm. Find the area.

This problem is solved by the formula for the middle line of a trapezoid through the area and height, the formula looks like this:
m = S / h
where m is the middle line, S is the area of the trapezoid, h is the height of the trapezoid
substituting the values we got it
6 = S / 5, from here we find S
S = m * h
S = 6 * 5
S = 30
Answer: the area of the trapezoid is 30 cm²