Given a trapezoid ABCD. angle A = 60, angle B = 120, angle D = 70. Find the angle C

A trapezoid is a quadrangle with two parallel sides.

The corners adjacent to the sides are one-sided corners.

The sum of one-sided angles for parallel lines and a secant is 180 °.

At the trapezium, the bases are parallel straight lines, and the lateral sides are secant.

Therefore, <A + <B = <C + <D = 180 °.

<C + 70 ° = 180 °.

<C = 180 ° – 70 ° = 110 °.

Answer: 110 °.



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