Given a trapezoid ABCD. Bases AB = 8 CD = 12 Height BK = 6. Find: a) the middle line; b) the area of the trapezoid.

univerkov | August 15, 2021 | education

The middle line of a trapezoid is equal to half the sum of the lengths of the bases of the trapezoid.

KM = (AB + CD) / 2 = (8 + 12) / 2 = 10 cm.

The area of the trapezoid is equal to the product of the midline and the height of the trapezoid.

S = KM * H = 10 * 6 = 60 cm2.

Answer: The middle line is 10 cm, the area is 60 cm2.

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