Given a trapezoid ABCD with a median line of 25, and AB = CD = 15. Find the perimeter

univerkov | April 18, 2021 | education

The middle line of the trapezoid is equal to half the sum of the lengths of the bases.

MP = (BC + AD) / 2.

Then (BC + AD) = MР * 2 = 25 + 2 = 50 cm.

The sum of the bases is 50 cm, and the sides, by condition, are 15 cm.

Determine the perimeter of the trapezoid.

P = (BC + AD) + AB + CD = 50 + 15 + 15 = 80 cm.

Answer: The perimeter of the trapezoid is 80 cm.

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