Given a triangle ABC, AB is equal to 4√2 AC is equal to √6, the angle A is equal to 60 degrees, find the area ABC.

univerkov | December 5, 2020 | education

Area = 1/2 product of the sides by the sine of the angle between them. Sine 60 = (√3) / 2, AB = 4√2, AC = √6. Therefore, S = 1/2 * 4√2 * √6 * (√3) / 2 = 6.
Answer: 6.

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