Given a triangle ABC, angle C is 90 degrees, angle A 30 AB is equal to √3 find AC.

We solve as follows. Since the hypotenuse AB = √3, the angle A = 30 °, then, based on the definition of the cosine of the acute angle of a right-angled triangle, we have: cos A = AC / AB, whence AC = AB / cos A = √3 / cos 30 ° = √ 3 / (√3 / 2) = 2.

Answer: AC side = 2 units.



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