Given a triangle ABC, the angle B is equal to 106 degrees, the angle C is 44 degrees.

Given a triangle ABC, the angle B is equal to 106 degrees, the angle C is 44 degrees. The bisector AM is drawn. Find the value of the angle MAC.

It is known that the sum of the interior angles of a triangle is 180 °. By condition, we know two angles: angle B = 106 °, angle C = 44 °. Find the third corner of the triangle, angle A:
Angle A = 180 ° – (106 ° + 44 °) = 180 ° – 150 ° = 30 °.
The bisector AM divides the angle A into two equal angles, we find the angle MAC:
Angle MAC = angle A / 2 = 30 ° / 2 = 15 °.
Answer: MAC angle = 15 °.