Given a triangle ABC, where angle A = 30 degrees, angle C = 135 degrees, side AB = 14cm. Find the side of CB.

univerkov | July 11, 2021 | education

Let’s apply the sine theorem for a triangle.

AB / SinACB = CB / SinBAC.

14 / Sin135 = CB / Sin30.

CB = 14 * Sin30 / Sin135 = 14 * (1/2) / (√2 / 2) = 14 / √2 = 7 * √2 cm.

Answer: The CB side is 7 * √2 cm.

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