Given a triangle ABC, where side BC = 5cm, side AC = 10cm, angle C = 60 degrees. Find side AB.
| July 11, 2021 | education
Let’s apply the cosine theorem for a triangle.
AB ^ 2 = AC ^ 2 + BC ^ 2 – 2 * AC * BC * CosACB = 10 ^ 2 + 5 ^ 2 – 2 * 10 * 5 * Cos60 = 125 – 100 * (1/2) = 125 – 50 = 75.
AB = √75 = 5 * √3 cm.
Answer: The length of the AB side is 5 * √3 cm.
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