Given a triangle whose angle 1 is greater than angle 2 by 20 degrees, and angle 2 is less

Given a triangle whose angle 1 is greater than angle 2 by 20 degrees, and angle 2 is less than angle 3 by 20 degrees, find the angles.

By the condition of the problem, a triangle is given.

Let’s designate the first corner of the triangle as “a” °.

Then, taking into account the condition of the problem, the second angle will be equal to “a – 20” °.

The third angle will be “a – 20 + 20” ° = “a” °, that is, the first and third angles are equal.

It is known that the sum of the three angles of a triangle is 180 °.

Let’s compose and solve the equation:

a + a + a – 20 = 180;

3a = 180 + 20;

3a = 200;

a = 200/3 = 66 2/3 ° is the first and third angles.

Let’s determine how many degrees the second angle of the triangle is:

66 2/3 – 20 = 46 2/3 °.