Given: ABC is a triangle, AB is 9, AC is 12, angle A is 30 degrees. Find the area of ABC.

To find the area of triangle ABC, you need to multiply the side AB by the side AC, then multiply by the sine of the angle between them, then divide the result by 2.

S = 9 cm * 12 cm * sin30 ° ÷ 2 = 108 cm² * 0.5 ÷ 2 = 27 cm².

Answer: the area of the triangle is 27 cm².



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