Given: ABCD trapezoid AB = CD BH | AD AH = 5 cm HD = 12 cm find: MN – middle line

The middle line of a trapezoid is equal to the half-sum of its bases:
MN = (BC + AD) / 2.
If the trapezoid is ABCD, AB = CD, then the trapezoid is isosceles.
In order to find the length of the base of the aircraft, we draw the height of the CК.
Since the trapezoid is isosceles, then KD = AH = 5 cm.
BC = HD – KD;
BC = 12 – 5 = 7;
AD = 5 + 12 = 17;
MN = (17 + 7) / 2 = 24/2 = 12.
Answer: the length of the middle line is MN = 12 cm.



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