Given an isosceles trapezoid ABCD. It is known that AB = CD (sides are equal)
Given an isosceles trapezoid ABCD. It is known that AB = CD (sides are equal) and BC = 3cm (base) and AD = 7cm (base) CA is the bisector of angle C. Find, P trapezoid.
The perimeter of a given trapezoid can be found using the following formula:
P = AB + BC + CD + AD.
We know the lengths of the sides BC and AD. It remains to find the sides BC and CD. They are equal.
Consider a triangle ACD. It is known that AC divides the angle C in half. Hence ACB angle = ACD angle. Also ACB angle = CAD angle, as cross overlapping angles. This means that the triangle ACD is isosceles, where AD = CD = 7 cm.
Now we know the lengths of all sides, and we can find the perimeter of the trapezoid. Let’s calculate it:
P = 7 + 3 + 7 + 7 = 24 cm.
Answer: the perimeter of the trapezoid is 24 cm.