Given an isosceles triangle ABC with base BC, now the bisector of angle B is half the bisector of angle A find: all angles of triangle A, B, C.
If the bisector of angle B is less than the bisector of angle A by half, then we can solve this problem through the equation.
Angle B = angle C, mk is an isosceles triangle.
Angle B = angle C = 2x, then angle A = 2x * 2 = 4x. The angles of a triangle add up to 180 °. Let’s make the equation:
2x + 2x + 4x = 180 °
x = 180/8 = 45 °, therefore the angle B = 45 ° and the angle C = 45 °. Angle A = 90 °.
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