Given an isosceles triangle, the sides of the AC and CB are 8 cm, the angle at the base is 35 degrees.

Given an isosceles triangle, the sides of the AC and CB are 8 cm, the angle at the base is 35 degrees. Find the area of the triangle ABC.

To find the area of a triangle, we will use the formula through two sides and the angle between them.
Find the angle C at the vertex of an isosceles triangle:
Angle C = 180 ° – (35 ° + 35 °) = 180 ° – 70 ° = 110 °.
We know the angle, let’s use the sine table. Sin 110 ° = 0.9396.
We find the area of a triangle as the half-product of the sides by the sine of the angle between them:
S = 1/2 * AC * CB * sin C = 1/2 * 8 * 8 * 0.9396 = 30.0672 ~ 30.07 cm².
Answer: the area of the triangle ABC is 30.07 cm².