Given: angle BAD = angle BCD = 90 degrees. Angle ADB = 15 degrees. BDC angle = 75 degrees. Prove AB is parallel to CD.
| December 7, 2020 | education
Decision:
<A + <BDA + <ABD = 180 degrees (the sum of the angles in a triangle is 180 degrees)
<ABD = 180- (A + <BDA)
<ABD = 180- (90 + 15) = 75 degrees
<ABD = <COB = 75 degrees
BD – secant
AB II CD, because when two intersecting straight lines cross the lying angles are equal, then the straight lines are parallel.
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