Given is an isosceles triangle ABC with base AC, B = 120, AB = 2. Find the base of the speaker.

Since the triangle ABC is isosceles, its sides are equal to BC = AB = 2 cm.

In the triangle ABC, by the cosine theorem, we define the length of the base of the AC.

AC ^ 2 = AB ^ 2 + BC ^ 2 – 2 * AB * BC * Cos120 = 4 + 4 – 2 * 2 * 2 * (-1/2) = 8 + 4 = 12.

AC = 2 * √3 cm.

Answer: The length of the AH base is 2 * √3 cm.



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