Given: KMNR- parallelogram; MN = 5 cm; MRN = 30; DN = 3 cm; MDN = 90 Find P parallelogram

KMNR is a parallelogram, therefore MN = KR = 5 centimeters by the parallelogram property.

Since the angle MDN = 90 degrees, the angle MDN = the angle NDR = 90 degrees.

Now consider the NDR triangle.

Side DN = 3 centimeters lies opposite the angle DRN = 30 degrees, therefore:

NR = DN * 2 = 3 * 2 = 6 centimeters (by the property of a right-angled triangle).

Since KMNR is a parallelogram, NR = MK = 6 centimeters.

Now we find the perimeter:

P = MK + MN + NR + KR = 6 + 6 + 5 + 5 = 22 centimeters.

Answer: The perimeter of the parallelogram is 22 centimeters.