Given point A (-1; 2), B (3; 2), C (0; 1) Find the length of the vector AB-4 AC.

To begin with, we find the length or modulus of the vector AB, where the modulus AB is equal to the square root of the sum of the squares of the difference in the coordinates of the points.
Therefore, the module AB = √ (3 + 1) 2 + (2 -2) 2 = 4.
Then the module AC = √ (0 + 1) 2 + (1 -2) 2 = √2.
Therefore, the length of the vector is: 4 – 4 * √2.
Then we write down the received answer: 4 – 4 * √2.



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