Given points A (2; -1), B (2; 3) and C (-1; -1) Find angle A.

Find the coordinates of vectors AB and AC:

AB = (2 – 2; 3 – (-1)) = (0; 4);

AC = (-1; -1 – (-1)) = (-3; 0).

The cosine of the angle between these vectors will be:

cos (A) = AC * AB / | AC | * | AB | = ((0 * (-3) + (4 * 0)) / 3 * 4 = 0

Then the angle A is equal to:

A = arccos (0) = 90.

Answer: 90 degrees.



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