# Given the reaction equation C + O2 = CO2 The mass of carbon is 60 grams Find:

**Given the reaction equation C + O2 = CO2 The mass of carbon is 60 grams Find: 1) The mass of carbon dioxide 2) The volume of oxygen (O2)**

To solve this problem, we write down given: m (C) = 60 g.

Find: the mass of carbon dioxide and the volume of oxygen.

Solution:

Let’s write down the reaction equation.

C + O2 = CO2

Let’s calculate the molar masses of carbon and carbon dioxide.

M (C) = 12 g / mol

M (CO2) = 12 + 16 * 2 = 44 g / mol

We write 60 g above the carbon, and 12 g below the carbon.

We write x g over carbon dioxide and 44 g under carbon dioxide.

Let’s compose and solve the proportion.

x = 60 * 44/12 = 220 g.

Above oxygen we write y l, and under oxygen we write a constant molar volume, which is 22.4 l / mol.

Let’s compose and solve the proportion.

y = 60 * 22.4 / 12 = 112 l

Answer: m (CO2) = 220 g; V (O2) = 112 HP