Given the solid substances chloride, nitrate and barium sulfate, suggest a method for their determination.

To determine each of the substances, you need to do the following.

First of all, using the solubility table, we determine whether there are any of these three salts that are insoluble. There is such a salt – barium sulfate. To determine which tube contains barium sulfate, simply add water. In test tubes with chloride and barium nitrate, the salt will dissolve. Barium chloride will remain as a precipitate.

The determination of the other two salts will require qualitative reactions for either the nitrate ion or the chloride ion. According to the solubility table, we see that there are no insoluble chlorides, but there are nitrates. So let’s add silver nitrate to both tubes. A white precipitate of silver chloride will precipitate in the barium chloride test tube.

BaCl2 + 2 AgNO3 = Ba (NO3) 2 + 2 AgCl

By elimination, we determine that the remaining test tube contained barium nitrate.



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