Given: trapezoid ABCD with bases BC AD angle CAD = 40 degrees, angle BDA = 30 degrees, Find the angles DBC, ACB.
| September 12, 2021 | education
At the trapezoid, the bases are parallel to each other. AD parallel to BC.
Then the diagonal AC is a secant intersecting two parallel straight lines, and therefore the angle DАС = DBC = 40 as cross-cutting angles at the intersection of parallel АD and ВС secant АС.
Similarly, BD is secant, and the angle ADB = ACB = 30.
Answer: DBC angle = 40, ACB angle = 30.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
