Given triangle ABC. AB = BC, BM-median. angle ABC = 110 °. find the corner ABM.
| September 6, 2021 | education
By the condition AB = BC, then the triangle ABC is isosceles.
In an isosceles triangle, the median drawn from apex to the base is also the height and bisector of that triangle.
Then the angle ABM = CBM = ABC / 2 = 110/2 = 55.
Answer: Angle ABM is 55.
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