Given: triangle ABC-isosceles, angle C = 25 ° Find: angle A and angle ABC.
| August 7, 2021 | education
The problem has two solutions, since the condition does not indicate the base of the triangle.
Let the base of the triangle be AB, then the angle CAB = CBA.
The sum of the inner angles of the triangle is 180, then the angle CAB = CBA = (180 – ACB) / 2 = (180 – 25) / 2 = 77.5.
Let the base of the triangle be AC, then the angle BAC = BCA = 25.
The sum of the inner angles of the triangle is 180, then the angle ABC = (180 – BAC – BCA) = (180 – 25 – 25) = 130.
Answer: Angle A = 77.5, angle B = 77.5, or angle A = 250, angle B = 130.
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