Given: triangle ABC-rectangular angle C = 90 degrees angle B = 45 degrees CH-height. Find: angle ASN.

Consider a triangle ABC. In it, the sum of the angles is 180 °, the angle C = 90 ° (according to the problem statement), the angle B = 45 ° (according to the problem statement). Hence,
angle A = 180 ° – (angle C + angle B) = 180 ° – (90 ° + 45 °) = 45 °,
angle A = 45 °.
Consider triangle ACH. In it, the sum of the angles is 180 °, the angle AHC = 90 ° (since CH is the height of the triangle ABC), and the angle found above is A = 45 °. Hence,
angle ACH = 180 ° – (angle AHC + angle A) = 180 ° – (90 ° + 45 °) = 45 °.
angle ACH = 45 °.
Answer: angle ACH = 45 °.