Given two cylinders, the radius of the base and the height of the first are equal to 6 and 9, respectively, and the second

| May 18, 2021 | education

Given two cylinders, the radius of the base and the height of the first are equal to 6 and 9, respectively, and the second, 9 and 2, how many times the volume of the first cylinder is greater than the volume of the second cylinder.

Let us first denote the size of each cylinder for convenience.
R1 = 6 – radius of the base of the first cylinder.
h1 = 9 – the height of the first cylinder.
R2 = 9 is the radius of the base of the second cylinder.
h2 = 2 is the height of the second cylinder.
Let’s find the volume of each cylinder.
The volume of the cylinder is equal to the product of the base area by the height:
V = ПR ^ 2h.
V1 = P * R1 ^ 2 * h1 = P * 6 ^ 2 * 9 = P * 36 * 9 = 324P – the volume of the first cylinder.
V2 = P * R2 ^ 2 * h2 = P * 9 ^ 2 * 2 = P * 81 * 2 = 162P – the volume of the second cylinder.
Now we can find out how many times the volume of the first cylinder is greater than the volume of the second cylinder.
324P: 162P = 2 (times) – the volume of the first cylinder is greater than the volume of the second cylinder.
Answer: the volume of the first cylinder is 2 times the volume of the second cylinder.



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