Given vectors a and b | a | = 2 | b | = √3 angle (a b) = 150 find | a-2b |
| July 4, 2021 | education
The angle between vectors a and -b is:
180 – 150 = 30 degrees.
Consider a triangle with sides a, 2b and an angle of 30 between them.The third side of the triangle is easy to find from the cosine theorem:
| a – 2b | ^ 2 = | a | ^ 2 + | b | ^ 2 – 2 * | a | * | b | * cos (30) = 4 + 3 – 8 * √3 * √3 / 2 = 6.
| a – 2b | = √6.
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