Group 5 element molecular weight 108, name the element and formulate the oxide and acid.

The general chemical formula of the higher oxide of the element (E) group 5 is E2O5.

Let the relative atomic mass (Ar) of the unknown element be x. Then the relative molecular weight of the oxide (Mr):

Мr (E2O5) = 2x + 5 Ar (O) = 2x + 5×16 = 2x + 80 = 108.

x = (108 – 80): 2 = 14.

In the PSCE we find that this is nitrogen N.

The formula for nitric oxide (V) is N2O5.

The formula for nitric acid is HNO3.



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