Half of the perimeter of the rectangle is 16 dm. Find the perimeter of the rectangle.

Half of the perimeter of the rectangle is 16 dm. Find the perimeter of the rectangle. Find the lengths of its sides if one is less than the other by 6 dm.

1. Find the perimeter of the rectangle, if half is 16 dm, for this we multiply 16 dm by 2:
Perimeter = 16 dm * 2 = 32 dm.
2. Let one of the adjacent sides of the rectangle be equal to x, then the other is equal to 6 + x. Doubling the sum of adjacent sides gives the perimeter. Let’s make an equation, find x:
2 * (x + 6 + x) = 32,
2 * (6 + 2x) = 32,
12 + 4x = 32,
4x = 32 – 12,
4x = 20,
x = 20/4,
x = 5 dm.
3. Find the second adjacent side:
6 + 5 = 11 dm.
Answer: the perimeter of the rectangle is 32 dm, and its adjacent sides are 11 dm and 5 dm.