Half of the perimeter of the rectangle is 16 dm. Find the perimeter of this rectangle.

Half of the perimeter of the rectangle is 16 dm. Find the perimeter of this rectangle. Find the lengths of their sides if one of the sides is 6 dm2 shorter than the other.

The first step is to calculate the perimeter of the rectangle:
1) 16 dm * 2 = 32 dm perimeter of the rectangle.
Let one side be x dm, then the other side is x-6 dm. The perimeter of a rectangle is calculated as the sum of its length and width multiplied by two.
P = 2 * (a + b)
2 * (x + x-6) = 32
2 * (2x-6) = 32
4x-12 = 32
4x = 32 + 12
4x = 44
x = 44/4
x = 11
Let’s calculate the value of the second side of the rectangle:
1) 11 dm – 6 dm = 5 dm the second side of the rectangle.
Answer: one side of the rectangle is 11 inches, the other side of the rectangle is 5 inches.