Hammer with mass m = 1t. falls from a height of h = 2m. on the anvil.

Hammer with mass m = 1t. falls from a height of h = 2m. on the anvil. Impact duration t = 0.01s. Determine the average value of the impact force.

m = 1t = 1000 kg.

h = 2 m.

g = 10 m / s2.

t = 0.01 s.

Fср -?

To find the average impact force Fav, we use 2 Newton’s law: Fav = m * a, where m is the mass of the hammer, a is the acceleration of the hammer when it strikes the anvil.

a = (V0 – V) / t.

Since V = 0 m / s, then a = V0 / t, Fav = m * V0 / t.

m * g * h = m * V0 ^ 2/2 – the law of conservation of total mechanical energy.

V02 = 2 * g * h.

V0 = √ (2 * g * h).

Fav = m * √ (2 * g * h) / t.

Fav = 1000 kg * √ (2 * 10 m / s2 * 2 m) / 0.01 s = 632455.5 N.

Answer: the average impact force of the hammer on the anvil is Fav = 632455.5 N.