Heat a steel rod with a mass of 600 g from 20s to 1020s. How much has the internal energy of the rod increased?

To calculate the increase in the internal energy of the steel bar under consideration, it is necessary to use the formula: Q = Cc * m * (t2 – t1), where Cc is the specific heat of carbon steel (Cc = 468 J / (kg * K)); m is the mass of the rod (m = 600 g = 0.6 kg); t2 – final temperature (t2 = 1020 ºC); t1 – temperature before heating (t1 = 20 ºC).

Let’s calculate: Q = 468 * 0.6 * (1020 – 20) = 280 800 J (280.8 kJ).

Answer: Internal energy has increased by 280.8 kJ.